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ariannanykole1
07.04.2020 •
Physics
A satellite is in elliptical orbit with a period of 7.20 104 s about a planet of mass 7.00 1024 kg. At aphelion, at radius 5.1 107 m, the satellite's angular speed is 4.987 10-5 rad/s. What is its angular speed at perihelion?
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Ответ:
1.64x
rad/s
Explanation:
Given:
satellite is in elliptical orbit with a period T= 7.20 x
s
Mass of planet m= 7.00x
kg
Satellite's angular speed ωa- = 4.987 10-5 rad/s
At aphelion, at radius Ra= 5.1 x 10^7 m
Assuming torque is zero for this system, therefore, the conservation of angular momentum can be defines as
Lp = La
Ip ωp = Ia ωa--->eq(1)
Where,
'a' represents aphelion and 'p' represents perihelion
ω represents angular velocity
and I represents the rotational inertia
Since, I= 1/2 mR²
Here R is the radius at aphelion / perihelion
m = mass of planet
eq(1)=> ωp= Ia ωa/ Ip
ωp= (1/2 m Ra² ωa) / 1/2 m Rp²
ωp= (Ra/Rp)² ωa --->eq(2)
In order to find Rp, we use : 2a= Rp + Ra
where a represents semimajor axis
with the help of Kepler's third law for elliptical orbits
a= ∛(GmT²/4π²)
a= ∛ 6.67x
x 7.00x
x (7.20 x
)² / 4π²
a= 3.97 x
m
2a= Rp + Ra
Rp= 2a-Ra
Rp= 2 x 3.97 x
- 5.1x ![10^{7}](/tpl/images/0587/2967/34f40.png)
Rp= 2.84 x
m
Substituting all the required values in eq 2, we have
ωp= (Ra/Rp)² ωa
ωp= (5.1x
/2.84 x
)² x 4.987 x ![10^{-5](/tpl/images/0587/2967/7836f.png)
ωp= 3.224 x 4.987 x![10^{-5](/tpl/images/0587/2967/7836f.png)
ωp= 1.64x
rad/s
Therefore, angular speed at perihelion is 1.64x
rad/s
Ответ:
E = 124.7 N / C
Explanation:
Let's analyze the exercise: the microwave creates an electromagnetic wave of frequency F = 2.45 GHz, this wave is introduced into the microwave cavity and is reflected on the metal walls, which is why one or more standing waves are formed.
The electric field of the standing wave is
I = E²
E =√I
where I is the intensity of the radiation.
What is it
I = P / A
where P is the effective emission power, almost all the power of the microwave and A is the area of the cavity, in the most used microwaves
P = 700 W and the area is A = 25 x 18 cm² = 0.045 m²
I = 700 / 0.045
I = 15555.56 W/m²
let's calculate the electric field
E = √15555.56
E = 124.7 N / C