A single conservative force acts on a 5.00-kg particle. The equation N, where x is in meters, describes this force. As the particle moves along the x axis from m to m, calculate (a) the work done by this force, (b) the change in the potential energy of the system, and (c) the kinetic energy of the particle at m if its speed at m is 3.00 m/s.

a)

b)

c)

Explanation:

a) The work is defined as the integral of the force from x₁ to x₂:

Here:

Now. we need to take the integral to get the work done:

b) The change of the potential energy is minus de work, so:

c) We know that the change in kinetic energy is equal to the work done, in a conservative system, so:

And know that:

We need to find the final kinetic energy, so let's solve it for Kf

I hope it helps you!

2.5m/s^2

Explanation:

to answer this question the best method would be to use SUVAT equations (attached)

here we have:

U= 0ms

v=25ms

t=10sec

a=?

the best equation to use in this instance is

v = u + at

substitute in the known values:

25=a10

25/10=a

2.5m/s^2 =a