mathman2428

21.04.2020 • 

Physics

A thin layer of oil (n = 1.38) on the ocean surface for thousands of miles. As an inspector, you are flying over the ocean surface in an aircraft, looking at a section of option where the oil thickness is 563 nanometers thick. You look straight down at the ocean, at a time of day when the sun is directly above you. a) So, if constructive interference occurs (i.e. where the reflection is brightest) what is the wavelength(s) of visible light in the reflection? b) However, in order to get a close-up look at the oil slick, you put on scuba gear and go diving under the portion of ocean you had been observing from the plane. For which wavelength(s) of visible light yield the strongest transmitted intensity?

Ответ:

Morganwing1019

24.01.2022

Physics

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Explanation:

The picture attached shows all the necessary explanations

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Ответ:

tyneshiajones124

14.01.2020

Physics

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Of course, with a triangle with a 90° angle, a right triangle, you can simply use pythagoras theorem  (a2+b2=c2)  then SOH-CAH-TOA to solve for the angle  (θ=Cos−1(adjacenthypotenuse)) .

But what if it isn't a right triangle? The cosine rule works for all triangles, even if they don't have a 90° angle.

a2=b2+c2−2(b)(c)Cos(A)  

Where a is the missing side, and A is the angle opposite to side a.

With this rule, we can find a missing angle or a missing side to any type of triangle, assuming you have the needed variables.

Explanation:

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