Physics: A transformer connected to a 120--V ac line is to supply 12.0V (rms) to a portable electronic device. The load resistance in the secondary is 4.70 ohms a. What should the ratio of primary to secondary turns of the transformer be? b. What rms current must the secondary supply? c. What average power is delivered to the load? d. What resistance connected directly across the source line (which has a voltage of 120?V ) would draw the same power as the transformer?

Explanation:This is simple logic. If the top can spin 6000 times before it starts to topple, and each minute the top can spin 800 times,6000/800 = 7.50 minutes...

A transformer connected to a 120--V ac line is to

Ответ:

bikerhomie

20.01.2022

Physics

Therefore,

a) $\dfrac{N_{1}}{N_{2}}=\dfrac{10}{1}$

b) I₂ = 2.55 Ampere

c) Power = 30.6 Watts

d) R₁ = 470.58 ohms.

Explanation:

Given:

Let the primary voltage be,

$V_{1}=120\ V$

Secondary Voltage,

$V_{2}=12\ V$

Secondary Resistance,

$R_{2}=4.7\ ohms$

To Find:

a) $\dfrac{N_{1}}{N_{2}}=?$

b) I₂ = ?

c) Power = ?

d) R₁ = ?

Solution:

The ratio of primary to secondary turns of the transformer, is the ratio of primary to secondary Voltage and is given by,

$\dfrac{N_{1}}{N_{2}}=\dfrac{V_{1}}{V_{2}}$

Substituting the values we get

$\dfrac{N_{1}}{N_{2}}=\dfrac{120}{12}=\dfrac{10}{1}$

For, rms current for the secondary supply,

$I_{2}=\dfrac{V_{2}}{R_{2}}$

Substituting the values we get

$I_{2}=\dfrac{12}{4.7}=2.55\ Ampere$

Now for average power at load,

$Power=V_{2}\times I_{2}$

Substituting the values we get

$Power=12\times 2.55=30.6\ Watts$

Now for resistance connected directly across the source line Power will remain same,

$Power=\dfrac{(V_{1})^{2}}{R_{1}}$

Substituting the values we get

$R_{1}=\dfrac{(V_{1})^{2}}{Power}=\dfrac{14400}{30.6}=470.58\ ohms$

Therefore,

a) $\dfrac{N_{1}}{N_{2}}=\dfrac{10}{1}$

b) I₂ = 2.55 Ampere

c) Power = 30.6 Watts

d) R₁ = 470.58 ohms.

0,0(0 оценок)

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Physics

Ask an AI advisor a question