A0.45 kg rock is projected from the edge of the top of a building with an initial velocity of 11.1m/s at an angle of 50 degrees above the horizontal. due to gravity, the rock strikes the ground at a horizontal distance of 16.9m from the base of the building. how tall is the building?
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Ответ:
1.67 m
Explanation:
Ux = 3 m/s, ax = -2.7 m/s^2, vx =0
Let the distance travelled before stopping along x axis is x.
Use third equation of motion along x axis
Vx^2 = ux^2 + 2 a x
0 = 9 - 2 × 2.7 × x
X = 1.67 m