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rebecca7415
24.07.2019 •
Physics
A1.00 kg object is attached to a horizontal spring. the spring is initially stretched by 0.400 m, and the object is released from rest there. it proceeds to move without friction. the next time the speed of the object is zero is 0.200 s later. what is the maximum speed of the object?
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Ответ:
v = 6.283 m/s
Explanation:
Given:
mass of the object, m = 1.00kg
The next time the speed is zero is at t = 0.200s i.e the one half of a total oscillation.
thus,
The time (T) for one complete oscillation will be = 2 × 0.200s = 0.4s
Now,
we know time period (T) is given as:
where, k is the spring constant
substituting the values in the above equation we get
or
or
k = 246.70 N/m
Then, using the concept of conservation of energy, we have
where,
x is the displacement in the spring
v = speed of the object
substituting the values in the above equation we get
or
or
v = 6.283 m/s (Answer)
Ответ:
F = 2200 * 3.4
F = 7480 Kg m/s²
So, your final answer is 7480