Physics: A100 w incandescent lightbulb emits about 5 w of visible light. (the other 95 w are emitted as infrared radiation or lost as heat to the surroundings.) the average wavelength of the visible light is about 600 nm, so make the simplifying assumption that all the light has this wavelength. how many visible-light photons does the bulb emit per second?

A100 w incandescent lightbulb emits about 5 w of

TheOriginalMeyah

11.01.2022

n = 1.89 x 10¹⁹ photons/s

Explanation:

given,

Power of bulb = 100 W

Visible light = 5 W

wavelength of the visible light = 600 nm

number of photons emitted per second

using formula of wavelength

$\lambda = \dfrac{c}{\nu}$

$\nu= \dfrac{c}{\lambda}$

$\nu= \dfrac{3 \times 10^8}{600 \times 10^{-9}}$

$\nu=5 \times 10^{14}\ Hz$

energy of photon

U = h υ

U = 6.63 x 10⁻³⁴ x 4 x 10¹⁴

U = 2.65 x 10⁻¹⁹ J

number of photon

$n = \dfrac{P}{U}$

$n = \dfrac{5}{2.65 \times 10^{-19}}$

n = 1.89 x 10¹⁹ photons/s

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angie249

11.03.2023

The pendulum has the most potential energy .

The pendulum has the least kinetic energy .

The pendulum has the most kinetic energy .

The pendulum has the least potential energy .

1) at the top of the swing

2) at the top of the swing

3) at the bottom of the swing

4) at the bottom of the swing

Explanation:

just did it, it's right. (EDGE 2020)

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