vapelordcarl69
27.09.2019 •
Physics
A15.0 kg cart is moving with a velocity of 7.50 m/s down a level hallway. a constant force of 10.0 n acts on the cart, and its velocity become 3.20 m/s.
a) what is the change in kinetic energy?
b) how much work was done on the cart?
c) how far did the cart move while the force acted?
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Ответ:
Below are the answers:
a. DE=421.875-76.8=-345.075 joules (negitive sign means that the energy is transfering out of your system ie slowing down)
b. work=DE (work done is change in energy)=-345.075 joules
c. W=f*d
d=w/f
d=345.075/10
d=34.5075 meters
Ответ:
Upthrust is the upward force exerted on a body immerses in a fluid.
Gravitational force is the foce of attraction on a body on other bodies
The force acting on the boat is upthrust while the force acting on the plane is the boat is gravitational force