Physics: A20 g ball of clay traveling east at 3.0 m/s collides with a 30 g ball of clay traveling north at 2.0 m/s. what are the speed and the direction of the resulting 50 g ball of clay?

A20 g ball of clay traveling east at 3.0 m/s collides

victoriapellam04

15.01.2022

1.697 m/s

Explanation:

m1 = 20 g

u1 = 3 m/s east = 3 i

m2 = 30 g

u2 = 2 m/s north = 2 j

Let the velocity is v after the collision

Use conservation of momentum

$m_{1}\overrightarrow{u_{1}}+m_{2}\overrightarrow{u_{2}}= \left ( m_{1}+m_{2} \right )\overrightarrow{v}$

$20\times 3\widehat{i}+30\times 2\widehat{j}= 50\overrightarrow{v}$

$1.2\widehat{i}+1.2\widehat{j}= \overrightarrow{v}$

v = 1.697 m/s

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cookiem0nster

26.01.2023

I don't know sorry

Explanation:

I don't know sorry

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