A200 n force is applied to a 50.0 kg object moving at 3.0 m/s. how fast will it be going at 4.0 s?

19.0 m/s

Explanation:

First of all, we can find the acceleration of the object by using Newton's second law:

where

F = 200 N is the net force applied to the object

m = 50.0 kg is the mass of the object

a is the acceleration

Solving for a,

Now we can find the final speed of the object:

where

u = 3.0 m/s is the initial speed

a = 4.0 m/s^2 is the acceleration

t = 4.0 s is the time

Substituting,

Explanation:

As B has a y component of -5, A must have a y component of 5 to have the result lie on the x axis.

As B has an x component of 3 and the result has an x component of -4, A must have an x component of -7

A = (-7, 5)

magnitude A = √(7² + 5²) = √74  ≈ 8.60

θ = arctan(y/x) = arctan(5/-7) ≈ 144.46° CCW from the positive x axis