Physics: A3.00 kg object rests upon a frictionless, horizontal floor. the object is attached to a horizontal spring (of force constant k = 485 n/m) whose other end is anchored to a nearby wall. the object is pulled until it lies a distance xi = 4.85 cm from its equilibrium position (x = 0). the object is then released and undergoes simple harmonic motion.

A3.00 kg object rests upon a frictionless, horizontal

GodlyGamer8239

13.01.2022

Time period =0.49

Angular frequency =12.71

Explanation:

As this block is released from equilibrium position to a distance of 4.85 cm it's amplitude is 4.85 cm.

For a body which undergoes simple harmonic motion it's angular frequency = $\sqrt{\frac{k}{m} }$ = $\sqrt{\frac{480}{3} }$ =12.71

Time period of this block = $\frac{2\pi }{angular frequency}=\frac{2\pi }{12.71}$ =0.49 seconds

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jaybeast40

06.11.2020

Explanation:

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