A4.01kg wood block is pressed against a vertical wood wall by a force applied at angle ϕ=33.0° to the horizontal. knight problem0552 image if the block is initially at rest, and μs=0.357, what force would you need to apply to begin moving the box up the wall?

The upward component of the applied force should be equal in magnitude to the sum of the block's weight and the force of static friction directed down. F sin(33) = F cos(33) ÎĽs + mg F sin(33) - F cos(33) ÎĽs = mg F (sin(33) - cos(33) ÎĽs) = mg F = mg / (sin(33) - cos(33) ÎĽs) F = (4.01 kg) (9.80 m/s^2) / (sin(33) - cos(33) (0.357)) F = 160 N We would need to apply a force of 160 N

Explanation:

Balancing the Hydrogen atoms on the right side,

Balancing the Oxygen atoms on the left side,

Reactants are on the left side: