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lilkassrocks
28.08.2019 •
Physics
A5.00-kg box slides 3.00 m across the floor before coming to rest. what is the coefficient of kinetic friction between the floor and the box if the box had an initial speed of 3.00 m/s?
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Ответ:
The coefficient of kinetic friction between the floor and the box is μ = 0.1529
Explanation:
Let's start calculating the weight of the box.
Given that
and gravity (g) is
the weight is :
Given that the box is sliding across the floor, the normal force is![49.05N](/tpl/images/0205/3261/e11f8.png)
Now, the work that the frictional force produces is equal to the kinetic energy variation that the box experiments.
ΔKE = Work frictional force
ΔKE = KEfinal - KEinitial ⇒
If![KE=\frac{1}{2}mv^{2}](/tpl/images/0205/3261/2ec44.png)
KEfinal = 0 J given that its speed is 0
ΔKE = KEfinal - KEinitial
ΔKE = 0 -![\frac{1}{2}(5.00kg).(3.00\frac{m}{s})^{2}](/tpl/images/0205/3261/6183d.png)
ΔKE = -22.5 J
The work that the frictional force produces is
Work frictional force = -(Frictional force).(distance)
The distance is 3.00 m
The frictional force is Nf.μ where Nf is the normal force and μ is the coefficient of kinetic friction between the box and the floor. We add a (-) given that the sense of the frictional force is opposite to the trajectory of the box.
Finally,
ΔKE = WFF
-22.5 J = - Nf.μ.d
μ =![\frac{22.5J}{(49.05N).(3.00m)}=0.1529](/tpl/images/0205/3261/b552b.png)
The coefficient of kinetic friction is 0.1529
Notice that this coefficient is dimensionless.
Ответ:
los neutrinos, sin embargo, participan en interacciones
Explanation: No lleva carga eléctrica. Sin embargo, el hecho de que los neutrinos participen en interacciones con otras partículas muestra que debemos tratar