htahir2345
09.11.2019 •
Physics
A92-kg skier is sliding down a ski slope that makes an angle of 30 degrees above the horizontal direction. the coefficient of kinetic friction between the skis and the snow is 0.10. neglecting any air resistance, what is the acceleration of the skier?
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Ответ:
a = 4.05 m/s²
Explanation:
Known data
m= 92 kg : mass of the skier
θ =30° :angle θ of the ski slope with respect to the horizontal direction
μk= 0.10 : coefficient of kinetic friction
g = 9.8 m/s² : acceleration due to gravity
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
We define the x-axis in the direction parallel to the movement of the block on the ramp and the y-axis in the direction perpendicular to it.
Forces acting on the skier
W: Weight of the skier : In vertical direction
N : Normal force : perpendicular to the ski slope
f : Friction force: parallel to the ski slope
Calculated of the W
W= m*g
W= 92kg* 9.8 m/s² = 901,6 N
x-y weight components
Wx= Wsin θ= 901,6 N *sin 30° = 450.8 N
Wy= Wcos θ = 901,6 N *cos 30° =780.8 N
Calculated of the N
We apply the formula (1)
∑Fy = m*ay ay = 0
N - Wy = 0
N = Wy
N = 780.8 N
Calculated of the f
f = μk* N= 0.10*780.8 N
f = 78.08 N
We apply the formula (1) to calculated acceleration of the skier:
∑Fx = m*ax , ax= a : acceleration of the block
Wx - f = m*a
450.8- 78.08 = ( 92)*a
372.72 = (92)*a
a = (372.72)/ (92)
a = 4.05 m/s²
Ответ:
In RLC circuit the frequency of the circuit is also known as resonance frequency of the circuit
It is calculated by
now for the maximum value of the capacitance we will use minimum frequency as they depends inversely on each other
Now for minimum value of the capacitance
So above is the values of maximum and minimum capacitance