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iamcuriousdelip08rmf
09.10.2019 •
Physics
Abus slows with constant acceleration from 24.0 m/s to 16.0 m/s and moves 50.0 m in the process. (a) how much further does it travel before coming to a stop? (b) how long does it take to stop from 24.0 m/s?
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Ответ:
(a) Bus will traveled further a distance of 40 m
(b) It will take 7.5 sec to stop the bus
Explanation:
We have given initial velocity of the bus u = 24 m/sec
And final velocity v = 16 m/sec
Distance traveled in this process s = 50 m
From third equation of motion we know that![v^2=u^2+2as](/tpl/images/0304/5760/94507.png)
(a) Now as the bus finally stops so final velocity v = 0 m/sec
So![v^2=u^2+2as](/tpl/images/0304/5760/94507.png)
s= 90 m
So further distance traveled by bus = 90-50 =40 m
(b) Now as the bus finally stops so final velocity v= 0 m/sec
Initial velocity u = 24 m/sec
Acceleration![a=-3.2m/sec^2](/tpl/images/0304/5760/8b3f4.png)
So time![t=\frac{v-u}{a}=\frac{0-24}{-3.2}=7.5sec](/tpl/images/0304/5760/8205b.png)
Ответ:
idk
Explanation: