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breannacaraballo
14.10.2019 •
Physics
Acar moving at 10.0 m/s encounters a bump that has a circular cross-section with a radius of 30.0 m. what is the normal force exerted by the seat of the car on a 60.0-kg passenger when the car is at the top of the bump?
a) 200 n
b) 389 n
c) 789 n
d) 589 n
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Ответ:
force at the top will be 388 N which is nearly equal to 389
option (b) is correct
Explanation:
We have given velocity of the moving car v = 10 m/sec
Radius of the circular section r = 30 m
Mass of the passenger m = 60 kg
Acceleration due to gravity![g=9.8m/sec^2](/tpl/images/0319/7318/d7979.png)
At the top normal force is given by![noraml\ force=mg-\frac{mv^2}{r}](/tpl/images/0319/7318/2ad5c.png)
So force at top will be![F=60\times 9.8-\frac{60\times 10^2}{30}=388N](/tpl/images/0319/7318/44008.png)
So force at the top will be 388 N which is nearly equal to 389
So option (b) is correct
Ответ:
option B
Explanation:
given.
car is moving at = 10 m/s
bump of radius = 30 m
normal force = ?
mass of the passenger = 60 kg
m × g = 60 × 9.81 N
normal force acting
=![mg - \dfrac{mv^2}{R}](/tpl/images/0319/7318/6e98e.png)
=![60\times 9.81 - \dfrac{60\times 10^2}{30}](/tpl/images/0319/7318/a7e9f.png)
=388.6 N
the normal force acting is equal to 389 N
hence, the correct answer is option B
Ответ:
m
Explanation: