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marine7643
03.12.2019 •
Physics
Acopper rod has a length of 1.3 m and a cross-sectional area of 3.6 10-4 m2. one end of the rod is in contact with boiling water and the other with a mixture of ice and water. what is the mass of ice per second that melts? assume that no heat is lost through the side surface of the rod.
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Ответ:
To solve the problem it is necessary to apply the concepts related to heat flow,
The heat flux can be defined as
Where,
k = Thermal conductivity
A = Area of cross-sectional area
d = Length of the rod
Replacing then,
From the definition of heat flow we know that this is also equivalent
Where,
Re-arrange to find![\dot{m},](/tpl/images/0401/5908/b1e81.png)
Therefore the mass of ice per second that melts is 0.032g
Ответ:
idk idk idk idk idk idk
Step-by-step explanation:
idk idk idk ikd