An aluminum sheet is compressed to a thickness of 2.0 microns. if each cubic centimeter of aluminum has a mass of 2.70 g, what is the mass of an aluminum sheet, in grams, if its total surface area is 5 m2

We need to find the volume V of the sheet of aluminum that has a thickness t of t=2 micrometers and that is equal to t= 2*10^6 m and area A = 5 m². Volume V is:

V=A*t= 5*2*10^-6 = 1*10^-5 m³. 

Now we need to find the volume V in cm³:

1 m³ = 1 000 000 cm³ so 10^-5 m³ = 10 cm³. 

If 1 cm³ has a mass of 2.70 g then 10 cm³ has a mass of 27.0 grams.

So the correct answer is the mass of the aluminum sheet is m= 27 g or m=0.027 kg. 

Explanation:

Centripetal acceleration is:

a = v² / r

a = (4.0 m/s)² / 0.60 m

a = 26.6 m/s²