An elevator and counterweight are like atwood’s machine. an elevator, m=100kg, has a counter weight m=90kg connected by a cable over a massless pulley with no friction. the elevator falls, starting from rest, a distance 20.5 m and lands. what the final kinetic energy of the system, in j, just before the elevator lands?
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Ответ:
v = 6.34 m / s
Explanation:
For this exercise let's use the concept of mechanical energy, write the energy of the system (elevator plus counterweight) at two points
Initial. Elevator highest point
The elevator mass is M and that of the counterweight m
Em₀ = U = M g h + mg (0)
The counterweight is on the floor
Final. elevated at the lowest point
as there is no friction
½ M v² + m g h = M g h
v² = (M-m) gh 2 / M
v = √ [(100-90) 9.8 20.5 2/100]
v = √ 40.18
v = 6.34 m / s
Ответ:
Resistor
Explanation: