Physics: An implanted pacemaker supplies the heart with 72 pulses per minute, each pulse providing 6.0 v for 0.65 ms. the resistance of the heart muscle between the pacemaker’s electrodes is 550 ω. find (a) the current that flows during a pulse, (b) the energy delivered in one pulse, and (c) the average power supplied by the pacemaker.

The value is and Explanation:From the question we are told that The image distance is The focal length is From the lens equation we have that = = Generally the magnification is = = ...

An implanted pacemaker supplies the heart with

Ответ:

xojade

09.03.2022

Physics

a) Current = 11 mA

b) Energy = 66 mJ

c) Power = 101.54 W

Explanation:

a) Voltage, V = IR

Voltage, V = 6 V, Resistance, R = 550 Ω

Current, I $=\frac{6}{550}=0.011A=11mA$

b) Energy = Current x Voltage = 6 x 0.011 = 0.066 J = 66 mJ

c) $\texttt{Power=}\frac{Energy}{Time}=\frac{0.066}{0.65\times 10^{-3}}=101.54W$

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Ответ:

joe7977

25.09.2021

Physics

The value is $v = 440 \ cm$

and

m = 16

Explanation:

From the question we are told that

The image distance is $v = 29 \ cm$

The focal length is $f = -31 \ cm$

From the lens equation we have that

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

=> $\frac{1}{-31} = \frac{1}{v} - \frac{1}{29}$

=> $v = 450 \ cm$

Generally the magnification is

$m = \frac{v}{u}$

=> $m = \frac{ 450}{29}$

=> m = 16

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