![ashleybashaam6821](/avatars/14206.jpg)
ashleybashaam6821
09.02.2021 •
Physics
An initially motionless test car is accelerated to 115 km/h in 8.58 s before striking a simulated deer. The car is in contact with the faux fawn for 0.815 s, after which the car is measured to be traveling at 60.0 km/h. What is the magnitude of the acceleration of the care before the collision? What is the magnitude of the average acceleration of the car during the collision?
Solved
Show answers
More tips
- C Computers and Internet How to Check the Speed of My Internet?...
- H Health and Medicine 10 Ways to Cleanse Your Colon and Improve Your Health...
- W Work and Career How to Write a Resume That Catches the Employer s Attention?...
- C Computers and Internet Е-head: How it Simplifies Life for Users?...
- F Family and Home How to Choose the Best Diapers for Your Baby?...
- F Family and Home Parquet or laminate, which is better?...
- L Leisure and Entertainment How to Properly Wind Fishing Line onto a Reel?...
- L Leisure and Entertainment How to Make a Paper Boat in Simple Steps...
- T Travel and tourism Maldives Adventures: What is the Best Season to Visit the Luxurious Beaches?...
- H Health and Medicine Kinesiology: What is it and How Does it Work?...
Answers on questions: Physics
- E English 1. How does the way in which fate affects Oedipus differ to Beowulf s response to the idea that the battle has been decided before it has been fought? 2. In light of Beowulf...
- C Computers and Technology In step 7, you listed three elements commonly listed in charts. what are all of those options? data points wordart a data series an x-axis a y-axis an icon a legend...
- H History Atahualpa attempted to gain freedom by offering to spy on other indigenous people promising francisco pizarro a room full of gold and silver giving the spanish their own city...
- P Physics PLZ help 10 points!!! space question!...
Ответ:
a) a = 3.72 m / s², b) a = -18.75 m / s²
Explanation:
a) Let's use kinematics to find the acceleration before the collision
v = v₀ + at
as part of rest the v₀ = 0
a = v / t
Let's reduce the magnitudes to the SI system
v = 115 km / h (1000 m / 1km) (1h / 3600s)
v = 31.94 m / s
v₂ = 60 km / h = 16.66 m / s
l
et's calculate
a = 31.94 / 8.58
a = 3.72 m / s²
b) For the operational average during the collision let's use the relationship between momentum and momentum
I = Δp
F Δt = m v_f - m v₀
F =![\frac{m ( v_f - v_o)}{t}](/tpl/images/1104/4835/4efe8.png)
F = m [16.66 - 31.94] / 0.815
F = m (-18.75)
Having the force let's use Newton's second law
F = m a
-18.75 m = m a
a = -18.75 m / s²
Ответ:
Traveled 30 meters. Took 6.0 or seconds seconds. and for the speed
Explanation: