Physics: An object is 18.0 cm to the left of a lens with a focal length of +9 cm. a second lens of focal length +13 cm is 29.5 cm to the right of the lens. find the location and size of the object of height 4.0 cm. location with respect to the second lens?

An object is 18.0 cm to the left of a lens with a

Ответ:

lovelyheart5337

31.12.2021

Physics

99.67 cm to the left of second lens

Explanation:

For the first lens :

$d_{o}$ = Distance of the object = 18 cm

= focal length of the lens = 9 cm

$d_{i}$ = Distance of the image

Using the lens equation

$\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}$

$\frac{1}{18} + \frac{1}{d_{i}} = \frac{1}{9}$

$d_{i} = 18$ cm

= distance between the two lenses = 29.5 cm

For the second lens, the image formed by the first lens acts as the object

For the second lens :

$d_{o}$ = Distance of the object = d - 18 = 29.5 - 18 = 11.5 cm

$d_{i}$ = Distance of the image

= focal length of the lens = 13 cm

Using the lens equation

$\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}$

$\frac{1}{11.5} + \frac{1}{d_{i}} = \frac{1}{13}$

$d_{i} = - 99.67$ cm

The image is located 99.67 cm to the left of the second lens

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Ответ:

Saberabuomar2007

27.10.2021

Physics

d Analyze and conclude

Explanation:

Whenever some experiment is conducted data is collected and recorded. Based on the data collected , data analysis is done and the results are formulated by arriving at appropriate conclusion .

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An object is 18.0 cm to the left of a lens with a focal length of +9 cm. a second lens of focal length +13 cm is 29.5 cm to the right of the lens. find the location and size of the object of height 4.0 cm. location with respect to the second lens?

Ответ:

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