Physics: An object is moving with an initial velocity of 23 m/s. it is then subject to a constant acceleration of 3.5 m/s2 for 12 s. how far will it have traveled during the time of its acceleration?

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An object is moving with an initial velocity of 23

jaylanmahone223

07.01.2022

528 m

Explanation:

We can solve the problem by using the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where

s is the displacement

u is the initial velocity

t is the time

a is the acceleration

In this problem,

u = 23 m/s

a=3.5 m/s^2

And substituting t = 12 s, we find the distance travelled:

$s=(23)(12)+\frac{1}{2}(3.5)(12)^2=528 m$

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