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06.03.2020 •
Physics
An object of mass 0.77 kg is initially at rest. When a force acts on it for 2.9 ms it acquires a speed of 16.2 m/s. Find the magnitude (in N) of the average force acting on the object during the 2.9 ms time interval. (Enter a number.)
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Ответ:
4.3KN
Explanation:f=m(v-u)/t
m=0.77kg
t=0.0029s
s=16.2m/s
F= 0.77*16.2/0.0029
F=12.474/0.0029
F= 4301.38N
F=4.3KN
Ответ:
B. Slow, steady growth increase
Explanation:
Reproductive age is a term used to refer to the time when members of a population have reached full sexual development and are able to generate offspring, that is, their bodies are ready to bear children.
If most of the population is below reproductive age, it means that this population will grow slowly, as most of its members cannot produce offspring. However, this population will reach reproductive age at some point, establishing steady growth. For this reason, we can say that the correct answer to your question is the letter B.