An object of mass m does the work of 16J having spring constant of 16 the square of displacememt is

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Ответ:

calvincdavis20981

01.01.2021

Physics

Rise in temperature is given as

$\Delta T = 8.4 \times 10^{-3} ^0C$

Explanation:

Initial kinetic energy of the block is given as

$KE = \frac{1}{2}mv^2$

here we will have

m = 3.3 kg

v = 3.2 m/s

now we will have

$KE = \frac{1}{2}mv^2$

now we will have

$KE = \frac{1}{2}(3.3)(3.2)^2$

KE = 17 J

now we know that 74% of initial kinetic energy is absorbed as internal energy of the block

so the rise in temperature of the block is given as

$KE = ms\Delta T$

$0.74 \times 17 J = (3.3)(452)\Delta T$

$12.5 = 1491.6 \Delta T$

$\Delta T = 8.4 \times 10^{-3} ^0C$

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