Physics: An object with a mass of 5.5 kg is allowed to slide from rest down an inclined plane. the plane makes an angle of 30º with the horizontal and is 72 m long. the coefficient of friction between the plane and the object is 0.35. the speed of the object at the bottom of the plane is

An object with a mass of 5.5 kg is allowed to slide

Ответ:

chrisd2432

13.01.2022

Physics

Velocity at the bottom will be 16.66 m/sec

Explanation:

We have given mass of the object m = 5.5 kg

Angle which is made by the plane $\Theta =30^{\circ}$

Distance traveled s = 72 m

Acceleration will be equal to $a=g(sin\Theta -\mu cos\Theta )=9.8\times (sin30^{\circ}-0.35cos30^{\circ})=1.929m/sec^2$

Initial velocity u = 0 m /sec

We have to find the velocity at the bottom of the plane, that is final velocity v

From third equation of motion we know that

v^2=u^2+2as

So $v^2=0^2+2\times 1.929\times 72=277.77$

v = 16.66 m/sec

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Ответ:

hebibova2016

10.10.2022

Physics

$v^{2}$ = $u^{2}$ + 2ar
$v^{2}$ = 0 + 2 * 9.8 m/s * (110 m - 10m)
v = $\sqrt{1960}$ = 44 m/s
if it is going down vertically. if there is some angle - it would be another story

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An object with a mass of 5.5 kg is allowed to slide from rest down an inclined plane. the plane makes an angle of 30º with the horizontal and is 72 m long. the coefficient of friction between the plane and the object is 0.35. the speed of the object at the bottom of the plane is

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