Astring is wrapped several times around the rim of a small hoop with radius 8.00 cm and mass 0.180 kg. the free end of the string is held in place and the hoop is released from rest (fig. e10.20). after the hoop has descended 75.0 cm, calculate (a) the angular speed of the rotating hoop and (b) the speed of its center.
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Ответ:
(a). The angular speed of the rotating is 33.8 rad/s.
(b). The speed of its center is 2.7 m/s.
Explanation:
Given that,
Radius = 8.00 cm
Mass = 0.180 kg
Height = 75.0 m
We need to calculate the angular speed of the rotating
Using conservation of energy
Here, initial velocity and angular velocity are equal to zero.
Here,
The angular speed of the rotating is 33.8 rad/s.
(b). We need to calculate the speed of its center
Using formula of speed
Put the value into the formula
Hence, (a). The angular speed of the rotating is 33.8 rad/s.
(b). The speed of its center is 2.7 m/s.
Ответ:
The correct answer is D, between sentence five and six
Explanation:
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