Rosalycarlite5358
26.01.2020 •
Physics
Asports car is advertised to be able to stop in a distance of 50.0 m from a speed is 99.0km/h. what is its acceleration in m/s2?
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Ответ:
The final speed is zero
The distance is 50.0m
Therefore you use the formula:
vfinal²=vinitial²+2ad
a=(vfinal²-vinitial²)/2d
= (0²-27.5²)/(2x50.0)
=-7.5625 or in correct sigdigs -7.56m/s²
Hope this helps!
Ответ:
Because 25% + 50% = 75%
And 75% of the students is 15 students.