harleyloveless2853
30.07.2019 •
Physics
Aspring-loaded piston-cylinder device is filled with 0.35 kg of water vapor that is initially at 4 mpa and 4000c. initially, the spring exerts no force against the piston. the spring constant in the spring-force relationship is k = 0.75 and the piston diameter is d = 20 cm. the water now undergoes a process until its volume is one-half of the original volume. calculate the final temperature and the specific enthalpy of the water.
Solved
Show answers
More tips
- C Computers and Internet How to Check the Speed of My Internet?...
- H Health and Medicine 10 Ways to Cleanse Your Colon and Improve Your Health...
- W Work and Career How to Write a Resume That Catches the Employer s Attention?...
- C Computers and Internet Е-head: How it Simplifies Life for Users?...
- F Family and Home How to Choose the Best Diapers for Your Baby?...
- F Family and Home Parquet or laminate, which is better?...
- L Leisure and Entertainment How to Properly Wind Fishing Line onto a Reel?...
- L Leisure and Entertainment How to Make a Paper Boat in Simple Steps...
- T Travel and tourism Maldives Adventures: What is the Best Season to Visit the Luxurious Beaches?...
- H Health and Medicine Kinesiology: What is it and How Does it Work?...
Answers on questions: Physics
- E English Which source would offer the most credible information about updates to traffic safety laws? a. a magazine article printed in july 2014 b. a book published in december 1990 c. an...
- M Mathematics How did the Germanic tribes contribute to the decline of the Western Roman Empire? Write your answer in a paragraph of 125 words. bs answers WILL be reported and points will be taken...
Ответ:
Read more on -
Ответ:
Given Information:
Magnetic field = B = 13.5 T
Circumference of circular ring = c = 39 km
Required Information:
Maximum energy = E = ?
Maximum energy = 4×10⁻⁶ Joules
Explanation:
A charged particle experiences a magnetic force due to the magnetic field is given by
F = qvB
Where q is the magnitude of charge, v is the velocity and B is the magnetic field.
Since the charged particle is moving in a circular ring, the centripetal force acting on it is given by
F = mv²/r
Where m is the mass of charged particle and r is the radius of the circular ring.
qvB = mv²/r
qB = mv/r
but mv = p that is linear momentum of the charged particle
qB = p/r
p = qBr
The energy is given by
E = pc
Substitute p = qBr
E = qBrc
Where c is the speed of light c = 2.99×10⁸ m/s
First find the radius,
c = 2πr
r = c/2π
r = 39×10³/2π
r = 6207 m
So the energy of the charged particle is
E = qBrc
E = (1.60×10⁻¹⁹)(13.5)(6207)(2.99×10⁸)
E = 4×10⁻⁶ Joules