Atruck on the freeway originally moving at 6.6 meters/second accelerates uniformly with acceleration a = 2.8 meters/second2 for 7.9 seconds. how far did the truck travel during that time interval?

139.514 metres

Explanation:

Initial velocity of the truck = 6.6 m/s

Acceleration of the truck = 2.8 m/s^2

Time interval = 7.9 s

Therefore we use the formula,

s = ut + 1/2 at^2

*where s(the distance travelled)...u(the initial velocity)...t(the time period)

; s = 6.6(7.9) + 1/2 (2.8)(7.9)^2

; s = 52.14 + 87.374

The distance moved by the truck = 139.514m

Correct  a₂ > a₁

Explanation:

Given:

Tony  mass = m₁ = 50 kg

Sam mass = m₂ = 45 kg

According to Newton's second law, the formula for calculating force is:

F = m · a

In this case we have the same force for both

F = m₁ a₁ = m₂ a₂  => a₁ / a₂ = m₂ / m₁ = 45 / 50 = 9 / 10 = 0.9

a₁ = 0.9 a₂  => a₁ = 90% of a₂ => a₂ > a₁

a₂ > a₁

God is with you!!!