Physics: Compare the moment of inertia of a disk of mass 2m and radius r about its central axis to the moment of inertia of a sphere of mass m and radius 2r.

Compare the moment of inertia of a disk of mass 2m

Ответ:

natashareeves16

31.12.2021

Physics

$\frac{I_{disc}}{I_{sphere}} = \frac{5}{8}$

Explanation:

As we know that the moment of inertia of the disc is given as

$I_{disc} = \frac{1}{2}mR^2$

here we know that

mass = 2m

radius = R

$I_{disc} = mR^2$

Now for sphere the moment of inertia is given as

$I_{sphere} = \frac{2}{5}mR^2$

here we know that

mass = m

radius = 2R

$I_{disc} = \frac{2}{5}m(2R)^2= \frac{8}{5}mR^2$

now the ratio of two moment of inertia is

$\frac{I_{disc}}{I_{sphere}} = \frac{mR^2}{1.6mR^2}$

$\frac{I_{disc}}{I_{sphere}} = \frac{5}{8}$

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Ответ:

heatherlemaster

02.05.2020

Physics

Complete question:

A bullet is shot straight up into the air from ground level. It reaches a maximum height at h = 739 m. Calculate the initial velocity of the bullet.

the initial velocity of the bullet is 120.35 m/s

Explanation:

Given;

maximum height reached by the bullet, h = 739 m

let the initial velocity of the bullet = u

At maximum height the final velocity of the bullet, v = 0

Apply the following kinematic equation to determine the initial velocity of the bullet.

v² = u² - 2gh

0 = u² - 2gh

u² = 2gh

u = √2gh

u = √(2 x 9.8 x 739)

u = 120.35 m/s

Therefore, the initial velocity of the bullet is 120.35 m/s

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Compare the moment of inertia of a disk of mass 2m and radius r about its central axis to the moment of inertia of a sphere of mass m and radius 2r.

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