Data Collection Team 1: Work
Power
Time
Team
Members
Force
(weight in Newtons) (seconds)
Distance
(meters)
556 N
Lindsey
5.5
20 m
620 N
6
Ellie
20 m
7
20 m
Krisy
597 N
20 m
6.5
Abbie
600 N
20 m
5
Breylee
580 N

Explanation:

Given that,

Mass of kara car m =1300kg

Velocity at which kara car was moving Vi =11m/s

The car stopped after t= 0.14sec

Therefore the final velocity is Vf = 0m/s

a. What is the change in momentum?

Change is momentum can be determine using

∆p = ∆MV

∆p = M∆V

∆p = m(Vf-Vi)

∆p = 1300(0-11)

∆p = 1300×-11

∆p = —14,300 kgm/s

The change in momentum of kara's car is —14,300kgm/s.

b. Impulse felt be kara car?

Impulse can be determine by using Newton second law of motion

Ft = ∆p

Impulse is Ft

I = ∆p = -14,300kgm/s.

Then, the impulse felt by Kara's car is -14,300kgm/s

c. Magnitude of force experienced by Kara's car?

From the impulse formula,

Ft = ∆p

Therefore,

F = ∆p/t

F = -14,300/0.14

F = -102,142.9N.

F ≈ —102,143N

The force experienced by kara's is -102,143N.

We can also determined the deceleration of Kara's car

From Newton second law

F=ma

Then, a = F/m

a = -102,143/1300

a = -78.57m/s²

The negative sign show deceleration

We can also calculate the distance the car moved before coming to halt.

Using equation of motion

X =ut+½at²

X = 11×0.14 + ½(-78.57) × 0.14²

X = 1.54 —0.77

X = 0.77m