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Dericktopsom
28.06.2019 •
Physics
Data encountered in solving problems often do not fall exactly on the grid of values provided by property tables, and linear interpolation between adjacent table entries becomes necessary. using the data provided here, estimate: (a) the specific volume at t = 120of, p = 54 lbf/in2 , in ft3 /lb. (b) the temperature at p = 60 lbf/in2 , v = 5.982 ft3 /lb, in of. (c) the specific volume at t = 110of, p = 58 lbf/in2 , in ft3 /lb.
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Ответ:
Friction force is 10.025 N
Solution:
As per the question:
Mass, m = 66 kg
Now,
We know that the value of the coefficient of friction for the knee joint fluid,
Now,
The friction force is given by:
N = Normal reaction force = weight = mg