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keshan3000
09.09.2019 •
Physics
Determination of thermal conductivity. in determining the thermal conductivity of an insulating material, the temperatures were measured on both sides of a flat slab of 25 mm of the material and were 318.4 and 303.2 k. the heat flux was measured as 35.1 w/m2. calculate the thermal conductivity in btu/h-ft-ºf and in w/m-k q = 35.1 w/m 2 t 1 = 318.4 k t 2 = 303.2 k 25 mm
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Ответ:
k=0.0577w/mk
k=0.03338BTU/h-ft-ºF
Explanation:
First we use the equation for heat transfer by conduction and solve for K
Q=KA(T2-T1)/x
Where
q=heat
A=area
T=temperature
K=conductivity
x=thickness
solving for k
k=Qx/A(T2-T1)
Q/A=Heat flux=q
k=qx/(T2-T1)
k=35.1*0.025/(318.4-303.2)
K=0.0577w/mk
remember that 1 btu / hftk equals 1,729 w / mk
K=0.0577/1.729=0.03338BTU/h-ft-ºF
Ответ: