Physics: Find the angle for the third-order maximum for 591 nm wavelength light falling on a diffraction grating having 1460 lines per centimeter.

Find the angle for the third-order maximum for 591 - id5912131697, yagalneedshelp8338

niti1409

01.01.2022

15.32°

Explanation:

We have given the wavelength $\lambda =591nm=591\times 10^{-9}m$

Diffraction grating is 1460 lines per cm

So $d=\frac{10^{-2}}{1460}=6.71\times 10^{-6}m$ (as 1 m=100 cm )

For maximum diffraction

$dsin\Theta =m\lambda$ here m is order of diffraction

So $6.71\times 10^{-6}sin\Theta =3\times 591\times 10^{-9}$

$sin\Theta =0.264$

$\Theta =15.32^{\circ}$

0,0(0 оценок)

jaimes04

04.06.2022

I'm good

Explanation:

AMEN

0,0(0 оценок)