Physics: g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approximately 98 cm/s. The blood volume traverses the aortic arch, exiting with the same speed but opposite direction. Assume the mass density of the blood is 1060 kg/m3 blood, the aortic arch remains stationary, and that the heart rate is 61 bpm. What is the average force exerted by the blood on the wall of the aorta.

y=1/2x-3 i thinkStep-by-step explanation:...

g During the contraction of the heart, 65 cm3

joseestrada27

11.02.2022

The force is $F = 0.1441 \ N$

Explanation:

From the question we are told that

The volume of blood ejected is $V_b = 65cm^3 = 65*10^{-6} \ m^3$

The velocity of the ejected blood is $v = 98 cm/ s = 0.98 \ m/s$

The mass density of blood is $\rho = 1060 \ kg/m^3$

The heart rate is $R = 61 bpm(beats \ per \ miunite) = \frac{61}{60} = 1.0667\ bps$

Generally the average force exerted is mathematically represented as

$F = 2 * \rho * V_b * R * v$

=> $F = 2 * 1060 * (65*10^{-6}) *1.0667 * 0.98$

=> $F = 0.1441 \ N$

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