Physics: Glenn is heating water in teakettle. the hot water at the bottom of the kettle rises. the cooler water near the top sinks and warms. which kind of transfer of heat is this ?

Glenn is heating water in teakettle. the hot water

Ответ:

lilquongohard

28.06.2022

Physics

35870474.30504 m

Explanation:

r = Distance from the surface

T = Time period = 24 h

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

m = Mass of the Earth = 5.98 × 10²⁴ kg

From Kepler's law we have relation

$T^2=\frac{4\pi^2r^3}{GM}\\\Rightarrow r=\frac{T^2GM}{4\pi^2}\\\Rightarrow r=\left(\frac{(24\times 3600)^2\times 6.67\times 10^{-11}\times 5.98\times 10^{24}}{4\pi^2}\right)^{\frac{1}{3}}\\\Rightarrow r=42250474.30504\ m$

Distance from the center of the Earth would be

$42250474.30504-6.38\times 10^6=35870474.30504\ m$

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Glenn is heating water in teakettle. the hot water at the bottom of the kettle rises. the cooler water near the top sinks and warms. which kind of transfer of heat is this ?

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