How long would it take Jesse with the acceleration of -2.50 m/s to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop

Time taken by Jesse to bring his bicycle =5.4 Sec

Explanation:

acceleration of bicycle = -2.5  m/sec²

Initial velocity of by cycle u =13.5 m/sec,

final velocity of bicycle v = 0 (since bicycle completely stop finally)

Let the time taken to stop the bicycle completely = t sec

We now by equation of motion,

putting the value of u,v & a in the equation

0=13.5 -2.5 x t ( a is taken as negative since velocity of bicycle is reducing)

= 5.4 Sec

210

Explanation:

A ball rolls horizontally off the cliff at a speed of 30 m/s. It takes 7 seconds for the ball to hit the ground. What is the height of the cliff and the horizontal distance traveled by the ball?

S = (1/2)*9.8 m/s^2 * 7^2 = 240.1 m if the ball is very dense so air resistance, and therefore terminal velocity, can be ignored.

S = v * t = 30 m/s * 7 s = 210 m for the horizontal distance, again assuming negligible air resistance.