If a cannonball were launched horizontally (launch angle of 0) with a speed of 37m/s from a height of 15m, how long would the cannonball remain in the air?
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Ответ:
Tenemos que la relación es T₂ = 1,41T₁
Explanation:
El periodo (T) en un sistema masa-resorte es:
En donde:
m: es la masa
k: es la constante del resorte
En el sistema de masa m, tenemos:
Y en el sistem de masa 2m:
La relación entre ellos se puede obtener haciendo T₁/T₂:
Entonces:
Por lo tanto, tenemos que la relación es T₂ = 1,41T₁
Espero que te sea de utilidad!