If a laser beam is red with a wavelength of 632.8 nm, what is the angle from the center of the airy disk to the first dark ring?

Answer

given,

wavelength of laser light = 632.8 nm

assuming that aperture of lens be equal to dia = 1 mm

now,

When laser light passes through aperture diffraction of light takes place

The first diffraction minima occurs at

       

where a is the width of aperture

λ is the wavelength of light

p is the angle

       

       

       

               p = 0.0363° angle of the first dark ring

Unfortunately, unless you include a picture of the hill, you can't solve for what would happen. However,
you can find KE from the question, and use that to determine how high it could go on the slope.
KE= 1/2 mv^2
1/2*1200*196 = 117600 Joules.

Hope this helped!