Physics: If a man walks 17 meters east then 17 meters south, the magnitude of the man s displacement is?

Sinceramente, no tengo idea, pero trate de escribir en inglés y ver si obtiene más respuestas. ¡Lo siento!...

If a man walks 17 meters east then 17 meters south,

michaireid04

03.01.2022

The magnitude of the displacement is 24.04 meters

Explanation:

Lets explain how to solve the problem

A man walks 17 meters east

Then 17 meters south

We need to find the magnitude of his displacement

Magnitude of displacement is a scalar quantity represents the distance,

as measured directly between the start point and the end point

Assume that the origin point is his starting point

East direction represented by positive part of x-axis

South direction is the negative part of the y-axis

The man walks 17 meters east, then his position at (17 , 0)

Then he walks 17 meters to south , his position is (17 , -17)

His starting position is at (0 , 0)

His final position is at (17 , -17)

The magnitude of displacement = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

The magnitude of displacement = $\sqrt{(17-0)^{2}+(-17-0)^{2}}$

The magnitude of displacement = $\sqrt{(17)^{2}+(-17)^{2}}$

The magnitude of displacement = $\sqrt{289+289}$

The magnitude of displacement = $\sqrt{578}=24.04$ meters

The magnitude of the displacement is 24.04 meters

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