josephmelichar777
11.07.2019 •
Physics
In a carnival booth, you can win a stuffed giraffe if you toss a quarter into a small dish. the dish is on a shelf above the point where the quarter leaves your hand and is a horizontal distance of 2.1 m from this point. if you toss the coin with a velocity of 6.4 m> s at an angle of 60° above
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Ответ:
The height of the coin above the point where the coin leaves your hand is 1.53 meters
"We are to find the height of the coin above the point where the coin leaves your hand is 1.53 meters"
Velocity, V = 6.4m/s
Angle, θ = 60°
Resolve the coin speed into vertical and horizontal components :
Horizontal component (Vx) :
Vx = Vcosθ
Vx = 6.4cos60° = 6.4 × 0.5 = 3.20 m/s
Vertical component (Vy) :
Vy = Vsinθ
Vy = 6.4 × sin60° = 6.4 × 0.8660 = 5.54 m/s
Time taken by the coin to reach the plate :
Recall :
Speed = distance / time
Time taken = distance / speed
Horizontal Distance = 2.1 m
Speed = horizontal velocity = 3.2 m/s
Hence,
Time taken = 2.1 / 3.2 = 0.656 seconds
From the laws of motion :
S = ut + 0.5gt²
S = height or vertical distance
u = vertical speed
g = acceleration due to gravity = - 9.8m/s (downward motion)
S = (5.54 × 0.656) + (0.5 × - 9.8 × 0.656²)
S = 3.635625 - 2.11025390625
S = 1.52537109375
S = 1.53 meters
Hence, the height of the coin above the point where the coin leaves your hand is 1.53 meters.
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Ответ:
components of the speed of the coin is given as
now the time taken by the coin to reach the plate is given by
now in order to find the height
so it is placed at 1.52 m height
Ответ:
Yo
Explanation:
Yes this is fact