In the diagram, q1 = +6.39*10^_9 C and q2 = +3.22*10^-9 C. What is the
electric potential at point P?
Include a + or - sign.

The electric potential will be "259.695 volt".

Explanation:

In the given question, the figure is not provided. Below is the attached figure given.

Given:

Now,

At point P, the electric potential will be:

⇒

By putting values, we get

⇒    

⇒    

h^2 - ( 2t_o v_s + 2v_s^2 /g) h + v_s^2  \  t_o^2 =0

The correct result is that of a positive height

Explanation:

For this exercise we use the kinematic relations, let's start by finding the time it takes for the sound to reach the man

             v_s = y / t

             t =

this height is y = h

             t =  \frac{h}{ v_s}

the man has a response time of t = t₀, therefore

time to move is

             t' =  t - t₀

the initial height of flower pot is

           y = y₀ + v₀ t' - ½ g  t'²

when it reaches the floor the height is zero y = 0 and as the pot is dropped its initial velocity is zero v₀ = 0

            0 = y₀ +0 - ½ g (t -t₀)²

if the initial height is i = h,

            h = ½ g ( - t₀)²2

            = - + t₀²

            h2 / vs2 - (2nd / vs + 2 / g) h + to2 - = 0

To know the height, you must solve the second degree equation, it is much easier with numerical values.

             The correct result is that of a positive height