zaehairston78531
16.03.2020 •
Physics
KATZPSEF1 30.P.041. My Notes Ask Your Teacher A charged particle enters a region of space with a uniform magnetic field B = 1.98 i T. At a particular instant in time, it has velocity v = (1.46 ✕ 106 i + 2.42 ✕ 106 j) m/s. Based on the observed acceleration, you determine that the force acting on the particle at this instant is F = 1.60 k N. What are the following?(a) the sign of the charged particle
(b) the magnitude of the charged particle
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Ответ:
The charge on the particle is positive
While the magnitude = 0.00028C
Explanation:
Please find the attached file for the solution
Ответ:
Explanation:
base of triangular frame, b = 90 cm
Area, A = 765 cm²
Let the height is h.
Area of a triangular frame = 1/2 x base x height
765 = 0.5 x 90 x h
h = 17 cm
Thus, the height of triangular frame is 17 cm.