L. An arrow is shot at 35° above the horizontal. Its velocity is 52 m/s and it hits the target. a. What is the horizontal velocity? (Show Work!)

The horizontal component of the velocity is approximately 42.6 m/s

Explanation:

The given parameters are;

The speed of the arrow when it was shot = 52 m/s

The angular direction in which the arrow was shot, θ = 35° above the horizontal

The horizontal component of the velocity is found by the resolution if the velocity vector into its components as follows;

The horizontal component of the velocity = Velocity in the x-direction = vₓ

vₓ = v × cos(θ) = 52 × cos (35°) ≈ 42.6 m/s

vₓ = The horizontal component of the velocity ≈ 42.6 m/s

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