Physics: Momentum: a satellite, initially at rest in deep space, separates into two pieces, which move away from each other. one piece has a mass of 190 kg and moves away with a speed 0.280 c, and the second piece moves in the opposite direction with a speed 0.600 c. what is the mass of the second piece?

Momentum: a satellite, initially at rest in deep

annikacorrea

16.03.2022

m = 73.88 kg

Explanation:

total momentum = 0

P_1 +P_2 = 0

P_1 =P_2

WE KNOW THAT MOMENTUM IS GIVEN BY:

$P_1 =\frac{mv_1}{\sqrt{1 -\frac{v_1^2}{c^2}}} [tex] =\frac{190*.280}{\sqrt{1 -\frac{0.280^2}{c^2}}}$

= 55.41c

second momentum with light velocity

P_2 =- P_1

$\frac{mv_2}{\sqrt{1 -\frac{v_2^2}{c^2}}} = 55.41c$

$mv_2 =5541c *\sqrt{1 -\frac{v_2^2}{c^2}$

$m *0.600c = 55.41c *\sqrt{1 -\frac{0.600^2}{c^2}$

solving for m we get

m = - 73.88 kg

-ve show that second mass moves in opposite direction to first mass.

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melanyaguirre25

17.08.2021

The value is $N = 2.69 *10^{26} \ photons$

Explanation:

From the question we are told that

The power is $P = 510 \ W$

The wavelength is $\lambda = 10.5 \ cm = 0.105 \ m$

Gnerally the number of photon produced is mathematically represented as

$N = \frac{P * \lambda }{ h * c }$

Here is the Planck's constant with a value $h = 6.62607015 * 10^{-34} J \cdot s$

c is the speed of light with value $c = 3.0*10^{8 } \ m/s$

$N = \frac{ 510 * 0.105 }{ 6.62607015 * 10^{-34} * 3.0 *10^{8} }$

=> $N = 2.69 *10^{26} \ photons$

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