Mr Johnson launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how much time does it take before the arrow hits the ground below (step 1 of a quesiton will need this answer for a future question) a 2 seconds
b. 1 second
c.4 seconds
d 19.6

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Ответ:

GaySpaghetti

23.03.2023

Physics

421 m

Explanation:

In a uniform circular motion, the centripetal force is given by:

$F=m\frac{v^2}{r}$

where

m is the mass of the object

v is the tangential speed

r is the radius of the circular trajectory

In this problem, we have:

F = 640 N

m = 1500 kg

v = 13.4 m/s

So, we can re-arrange the equation to find the radius of the curve, r:

$r=\frac{mv^2}{F}=\frac{(1500 kg)(13.4 m/s)^2}{640 N}=420.8 m\sim 421 m$

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Mr Johnson launches an arrow horizontally at a rate of 40m/s off of a 78.4 m cliff towards the south, how much time does it take before the arrow hits the ground below (step 1 of a quesiton will need this answer for a future question) a 2 secondsb. 1 second c.4 seconds d 19.6