Ohhhhhh........needing help again......

A

Explanation:

Point a is the highest. When it comes to potential energy, the higher you are, the more of it you have. Example, when you are at the top of a hill, you have the most potential energy. When you are at the bottom of the hill, you have the least amount of potential energy, and the most kinetic energy.

Hope this helps!!

Explanation:

The amplitude of the oscillation under SHM will be .5 m and the equation of

SHM can be written as follows

x = .5 sin(ωt + π/2) , here the initial phase is π/2 because when t = 0 , x = A ( amplitude) , ω is angular frequency.

x = .5 cosωt

given , when t = .2 s , x = .35 m

.35 = .5 cos ωt

ωt = .79

ω = .79 / .20

= 3.95 rad /s

period of oscillation

T = 2π / ω

= 2 x 3.14 / 3.95

= 1.6 s

b )

ω =

ω² = k / m

k = ω² x m

= 3.95² x .6

= 9.36 N/s

c )

v = ω

At t = .2 , x = .35

v = 3.95

= 3.95 x .357

= 1.41 m/ s

d )

Acceleration at x

a = ω² x

= 3.95 x .35

= 1.3825 m s⁻²