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Ответ:

karsynraine8224

24.09.2022

Physics

Answer

given,

wavelength (λ) = 650 nm

angle = 5°

using bragg's law

$sin \theta = \dfrac{n \lambda}{d}$

$d= \dfrac{n \lambda}{sin \theta}$

$d= \dfrac{1 \times 650 \times 10^{-9}\ m}{sin5^0}$

d = 7.46 x 10⁻⁴ cm

number of slits per centimeter

= $\dfrac{1}{d}\\\Rightarrow \dfrac{1}{7.46\times 10^{-4}}\\\Rightarrow 1340 split per centimeter.$

b) wavelength of two rays 650 nm and 420 nm

$d = \dfrac{1}{5000}$

d = 2 x 10⁻6 m

we now,

$sin \theta = \dfrac{n \lambda}{d}$

for 650 nm

$sin \theta = \dfrac{2\times 650\times 10^{-9}}{2\times 10^{-6}}$

$\theta =sin^{-1}(0.65)$

θ = 40.54°

for 450 nm

$sin \theta = \dfrac{2\times 450\times 10^{-9}}{2\times 10^{-6}}$

$\theta =sin^{-1}(0.45)$

θ = 24.83°

now, difference

|θ_{650} -θ_{420}| =40.54°-24.83°

|θ_{650} -θ_{420}| =19.71°

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