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Jenifermorales101
03.07.2019 •
Physics
Sand falls from an overhead bin and accumulates in a conical pile with a radius that is always twotwo times its height. suppose the height of the pile increases at a rate of 33 cm divided by scm/s when the pile is 1010 cm high. at what rate is the sand leaving the bin at that instant?
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Ответ:
-423 m³/s
Explanation:
Volume of a cone is:
V = ⅓ π r² h
Given r = 2h:
V = ⅓ π (2h)² h
V = ⁴/₃ π h³
Taking derivative with respect to time:
dV/dt = 4π h² dh/dt
Given h = 1010 cm and dh/dt = 33 cm/s:
dV/dt = 4π (1010 cm)² (33 cm/s)
dV/dt ≈ 4.23×10⁸ cm³/s
dV/dt ≈ 423 m³/s
The pile is growing at 423 m³/s, so the bin is draining at -423 m³/s.
Ответ: